(p-6)^(3/2)=80/p

Solution for (p-6)^(3/2)=80/p equation:

(p-6)^(3/2)=80/p

We move all terms to the left:

(p-6)^(3/2)-(80/p)=0


Domain of the equation: p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(p-6)^(+3/2)-(+80/p)=0

We get rid of parentheses

(p-6)^(+3/2)-80/p=0

We calculate fractions


((p-6)^(+3*p)/2*p)+()/2*p)=0


We calculate terms in parentheses: +((p-6)^(+3*p)/2*p), so:

(p-6)^(+3*p)/2*p

We add all the numbers together, and all the variables

(p-6)^(+3p)/2*p

We multiply all the terms by the denominator


(p-6)^(+3p)

Back to the equation:

+((p-6)^(+3p))


We get rid of parentheses

((p-6)^(+3p))+)/2*p=0

We multiply all the terms by the denominator


(((p-6)^(+3p)))*2*p+)=0

We add all the numbers together, and all the variables

(((p-6)^(+3p)))*2*p=0